Math, asked by swastikrout1973, 7 months ago

a man made a trip of 480km in 9 hours.Some part of the trip was covered at 45km/hr and the remaining at 60 km/hr .Find the part of the trip covered by him at 60 km/hr​

Answers

Answered by singhpinki195
2

Work out this.

Total distance of trip =480km

Total time of journey =9 hrs

Let 'x' hrs be travel with 45 km/h and rest with 60 km/h

15x+60(9−x)=480

45x+450−60x=480

15x=60

[x=4]

Now, Total distance covered with 60 km/hr =60×5=300km.

The question is done thankyou.

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