A man made a will in which he left 4/9 of his
money to his wife and 2/5 of the remainder to
his eldest child. The rest was to be shared
equally among his four younger children .
If each of the younger children received
N 108 000, what was his wife's share? please show steps that are understandable
Answers
Answer:
N 1,080,000.
Step-by-step explanation:
The man left 4/9 of his wealth to his wife.
He left 2/5th of the remainder 5/9 (= 9/9 - 4/9) to his eldest son. So 2/5th of 5/9 = (2 × 5 = ) 10/45 (= 5 × 9) = 2/9.
The rest, ie 9/9 - (5/9 + 2/9 = ) 7/9 = 2/9 was to be shared equally among his children. So each younger child received 1/4th of 2/9 = (1 × 2)(4 × 9) = 2/36 = 1/18. 1/18th of that man's wealth = N 108,000.
So first we will convert the wife's share (5/9) to a fraction with denominator 18 = 10/18.
Therefore the money the wife received = N 108,000 × 10 = N 1,080,000.
Step-by-step explanation:
wife =4/9 of total amount
remaining amount =1-(4/9)= 5/9of total amount
eldest child =2/5 of remaining
=2/5×5/9 =2/9 of total amount
remaining amount = 1-2/9=7/9of total amount
let total amount =x
remaining amount =7x/9
shared among 4 younger children
= 7x/9 /4 = 108000
=7x/36=108000
x = 36×108000/7=555428.57
wife =4/9x = 246857.14