Question

A man moves 4m along east direction, then 3m along north direction, after that he climbs up a pole to a height 12m. find the distance covered by him and his displacement??

Answer 1

Apply Pythagorus Theorem on 3,4 you will get Hyp. 5 and then apply it on 5 and 12, we will get 13.as hyp. So net displacement is 13.

Answer 2

Answer: The distance is 19 m and the displacement is 15.5 m

Explanation:

Given that,

Distance along east direction = 4 m

Distance along north direction = 3 m

Height of pole = 12 m

We know that,

The total distance is

$d = 4m+3m+12m$

$d = 19 m$

Now, according to figure

The total displacement is

$AC = \sqrt{AB^{2}+BC^{2}}$

$AC = \sqrt{4^{2}+15^{2}}$

$AC = 15.5 m$

Hence, the distance is 19 m and the displacement is 15.5 m