Question

a man moves 4meter towards east and 3meter toward north calculate the distance and displacement covered by the man

Answer 1

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Answer 2

Q. A man moves 4meter towards east and 3meter toward north calculate the 
(a) distance 
(b) displacement 
covered by the man.

Solution :

(a) The distance travelled from O to Y
= OX + XY
= 4m + 3m
= 7m

(b) The displacement of the man is OY, which can be calculated by Pythagoras theorem, 

$OY = \sqrt{ {(OX)}^{2} + {( XY)}^{2} } \\ \\ OY = \sqrt{ {(4)}^{2} + {(3)}^{2} } \\ \\ OY = \sqrt{16 + 9} \\ \\ OY = \sqrt{25} \\ \\ OY = 5m$

Hence,
distance = 7m
displacement = 5m