Question

A man moving with a speed v down the inclined plane meets the rain horizontally with same speed .The actual velocity of rain is

Answer 1

Answer:

Explanation: FIRST OF ALL CONSIDER THE ANGLE OF ELEVATION OF INCLINE PLANE AS THETA.

NEXT RESOLVE THE MANS VELOCITY INTO RESPECTIVE COMPONENTS. YOU WILL GET VCOS THETA I CAP-VSIN THETA J CAP.

CONSIDER THE VELOCITY OF RAIN AS VX ICAP-VY J CAP. EQN 1

FIND VELOCITY OF RAIN WRT TO MAN AND EQUATE THE VERTICAL COMPONENT TO ZERO AND FIND OUT VY.

SIMILARLY EQUATE HORIZONTAL COMPONENT TO V[GIVEN IN THE QUESTION] AND FIND OUT VX.

SUBSTITUTE THESE VALUES IN EQN 1 AND THATS IT. YOU WILL GET YOUR ANSWER