Question

a man observes two vertical poles which are fixed deposit to the other on either side of the road if the width of the road is 90 feet and height of the pole are in the ratio 1:2 also the angle of elevation of the tops from a point between the line joining the foot of the poles on the roll is 60 degree find the height of the poles​

Answer 1

Answer:3

Step-by-step explanation:

Answer 2

The height of first pole $h_{1}$ = $x$  = 77.94 ft

The height of second pole $h_{2}$ = 2$x$ = 2 × 77.94 = 155.88 ft

Step-by-step explanation:

Since the height of the poles are in the ratio of 1 : 2

Height of first pole $h_{1}$ = $x$

Height of second pole $h_{2}$ = 2$x$

From Δ ABC

$\tan 60 = \frac{AB}{BC}$

Since AB = $x$ & BC = 45

⇒ $x = BC \tan60$°

⇒ $x$ = 45 $\tan60$

⇒ $x$  = 77.94 ft

Thus the height of first pole $h_{1}$ = $x$  = 77.94 ft

and height of second pole $h_{2}$ = 2$x$ = 2 × 77.94 = 155.88 ft