Question

a man observes two vertical poles which are fixed opposite to each other on either side of the road if the width of throw is 90 and height of the pole are in the ratio 1 is to 2 the angle of elevation of their tops from a point between the lines of the food of the poles on the road is 60 degree find the height of pole​

Answer 1

Answer:Let C be the point between the poles on the ground.

Since poles are vertical to the ground.

∠ADC = ∠ABC = 90°In a right-angled triangle, we know,

In ∆EDC

tan 60° =  

h = √3 --------(1)

In ∆ABC

tan 30° =  

√3h = 80-x----------(2)

On substituting value of h from eqn.(1) in eqn. (2)

√3 × √3x = 80 - x

⇒ 3x = 80 - x

⇒ 4x = 80

⇒ x = 20 m

On substituting value of  in eqn. (1)

h = 20√3

Distance of C from pole ED = 20 m

Distance of C from pole AB = 80 - 20= 60 m

Therefore the height of the poles is 20√3 m. and distances of the points from one pole is 20 m and from other pole is 60 m.

Step-by-step explanation: