A man of 1.5 m tall 28.5 m away from tower angle of elevation is 45 find height of tower
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Given the height of the observer be DE = 1.5 m
That is AB = 1.5 m
Let BC = h is height of the chimney
Hence AC = (h – 1.5) m
Given distance between the observer and the chimney is AD = BE = 28.5 m
In right DCAD, θ = 45°
∴ h = 28.5 +1.5 = 30 m
Thus the height of the chimney is 30
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