a man of 55 kg is holding a bucket of mass 25 kg. he walks 50 m on a level road at a constant speed of 3ms -1 and then climbs up a hill of hight 20m. the work done by the man is ( g = 10 ms -2 )
Answers
Answered by
12
first
force = mass × gravitation acceleration
f = 55 + 25 × 10
f = 80 × 10
f = 800 N
now ,
total distance covered by the man = 50 + 20
= 70 m
work done = force × displacement
w = 800 × 70
w = 56000 J
therefore work done by the man is 56000 J
force = mass × gravitation acceleration
f = 55 + 25 × 10
f = 80 × 10
f = 800 N
now ,
total distance covered by the man = 50 + 20
= 70 m
work done = force × displacement
w = 800 × 70
w = 56000 J
therefore work done by the man is 56000 J
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Answered by
9
Answer:
Explanation:
w = mgh
= 80*10*20J
= 16000J
= 16KJ
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