Question

A man of 60 kg moves in a lift of constant velocity 5 m/s. What is the reactive force acting on the man by the elevator?

Answer 1

Here, Waight of the man is 60kg, and velocity is 5m/s^-2..so. the reactive or upward force on the man by the lift or by the elevator is N=m(g+a)=60(9.8+5)=60*49=2940...

Answer 2

Answer:

N = 588 Newton

Explanation:

It is given that,

Mass of the man, m = 60 kg

It moves with a constant velocity, v = 5 m/s

Let N is the reactive force acting on the man by the elevator. We know that the reactive force is also known as normal force. The man under the action of gravity. So,

$N=m\times g$

$N=60\times 9.8$

N = 588 Newton

So, the reactive force acting on the man by the elevator is 588 N. Hence, this is the required solution.