A man of height 1.5 metres is standing and seeing a building of 58 metres with binoculars , if the angle he is seeing is 30
, find distance between building and the man
Answers
Answered by
1
Answer:
REF.Image
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
=28.5(
3
2
)=32.91m
Answered by
0
Answer:
REF.Image
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
=28.5(
3
2
)=32.91m
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