Question

A man of mass 100 kg is running with a constant velocity of 5 m/s on a horizontal surface and an air resistance force equal
to one fifth of is weight is acting on him. Then calculate the rate at which the man needs to do work to maintain his speed.​

Answer 1

Explanation:

ANSWER

ANSWERConsider the problem

ANSWERConsider the problemGiven,

ANSWERConsider the problemGiven,The mass of the vehicle m=100kg

ANSWERConsider the problemGiven,The mass of the vehicle m=100kgThe initial velocity u=5m/s.

ANSWERConsider the problemGiven,The mass of the vehicle m=100kgThe initial velocity u=5m/s.The time required to stop the vehicle t=

ANSWERConsider the problemGiven,The mass of the vehicle m=100kgThe initial velocity u=5m/s.The time required to stop the vehicle t= 10÷1

1

1 sec i.e 0.1second.

1 sec i.e 0.1second.The final velocity of the vehicle v=0m/s.

1 sec i.e 0.1second.The final velocity of the vehicle v=0m/s.As per Newton's second law of motion, we know that force is equal to rate of change of momentum.

1 sec i.e 0.1second.The final velocity of the vehicle v=0m/s.As per Newton's second law of motion, we know that force is equal to rate of change of momentum. F= dt÷dp

Here F and p stands for force and momentum

Here F and p stands for force and momentum =m

Here F and p stands for force and momentum =m v−u÷t

=100

=100 0.1

=100 0.1[0−5]

=100 0.1[0−5]

=100 0.1[0−5] N

=100 0.1[0−5] N=−5000N

=100 0.1[0−5] N=−5000N

=100 0.1[0−5] N=−5000N

=100 0.1[0−5] N=−5000N The Negative sign indicates the force is in opposite direction

=100 0.1[0−5] N=−5000N The Negative sign indicates the force is in opposite direction Therefore, F=5000N

Answer 2

Answer:

hey dude

Explanation:

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