Question

A man of mass 50 kg stands on a frame of mass 30 kg he pulls on a light rope
which passes over a pulley. The other end of the rope is attached to the
frame. For the system to be in equilibrium what force man must exert on the
rope
(A) 40 g
(B) 80 g
(C) 30 g
(D) 50 g​

Answer 1

Answer:

Option (A) 40g

Explanation:

If the man and the frame are in equilibrium the total forces acting on the system must be equal to 0

Let the tension in the rope be T

Then as shown in the attached figure, if we take man and the frame as one system then the forces acting on this system will be

(1) Tension T in the rope attached to the frame (Upwards)

(2) Tension T the end of the rope being pulled by the man (Upwards)

(3) Weight of the man Mg (Downwards)

(4) Weight of the frame mg (Downwards)

Here M = 50 kg and m = 30 kg

Therefore, for the system to be equilibrium

T + T = (M + m)g

⇒ 2T = (50 + 30)g

⇒ 2T = 80g

⇒ T = 40g

Answer 2

Answer:

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