a man of mass 60kg standing on a light weighing machine kept in a box of mass 30kg .The box is hanging from the pulley fixed to the ceiling through a light rope the other end of which is held by the man himself. If the man manages to keep the box at rest, what is the weight shown by the machine? What force should he exert on the rope to get his correct weight on the machine?
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I think that weight will be 0 as the net force in downward direction is 0. The force exerted by the rope is the force of tension. When the body is at rest which means there is no net force, Force of tension= MG (Weight).
The answer is completed
.
For extra:-
when body is moving downward, then(T is less than mg)
net force = mg - T
when at rest, mg = T
So net force is 0
The answer is completed
.
For extra:-
when body is moving downward, then(T is less than mg)
net force = mg - T
when at rest, mg = T
So net force is 0
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