Physics, asked by raviguvvala123, 8 months ago

A MAN OF MASS 70 KG ASCENDS A FLIGHT of 36 STEPS EACH 20 CM HIGH .WORK DONE BY THE MAN AGAINST THE GRAVITATIONAL FORCE IS (g=9.8ms-2​

Answers

Answered by kandelhira20
2

Explanation:

mass is equal to 70 kg acceleration due to gravity d 9.8 metre per second square is equals to 20 CM work done equals to what we now to MGS 70 into 9.8 into 22 13720 dual therefore the work done of acceleration due to gravity is 13720 answer

Similar questions