if A, B and C are interior angles of triangles ABC, then so that tan (A+B)/2=cotC/2
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Step-by-step explanation:
A+B+C=180. [·.·angle sum property]
divide both sides by 2
A+B/2=180-c/2
A+B/2=90-c/2
apply tan on bothsides
tan(A+B)=tan(90-c/2)
tan(A+B)=cot C/2. [·.·tan(90-C)=cot C]
·.·Hence proved
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