Question

A man of mass 70 kg is holding a block of mass 10kg the reading of machine is

Answer 1

Given:-

• Mass of man, m" = 70kg

• Mass of block, m' = 10kg

To Find:-

• Weight ,w

Solution:-

Firstly we calculate the Total mass

→ m = m" + m'

→ m = 70 kg + 10kg

→ m = 80kg

As we know that the weight machine measure the weight of the object.

The acceleration due to gravity on the earth's surface is 9.8m/s²

• W = mg

Substitute the value we get

→ W = 80×9.8

→ W = 8×98

→ W = 784N

Therefore, the machine reading 784 Newton.

Additional Information!!

✧ Product of mass and acceleration is called force.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀OR

A push or pull of an object is called force.

✧ SI unit of Force is Newton.

✧ It is denoted by N.

✧ Force is vector Quantity i.e., both Magnitude and direction.

✧ Mathematical term

• F = m×a

Answer 2

Solution

Given,

• mass of man = 70kg (m2)
• mass of block = 10kg (m1)

To find ,

• we have to find here to weight .

So,

we have to put calculate the total mass to find out the weight ;

$\bold{m = m_{1} \: + m_{2}}$

$= > m = 70kg + 10kg$

$= > m = 80kg$

so the total mass is 80 kg .

• N.B. - to find the weight will know that ; W =mg
• and the acceleration due to gravity value is 9.8 m/s^2

now putting the value we get ;

$\bold{w = mg}$

$= > w = 80 \times 9.8$

$= > w = 8 \times 98$

$= w = 784n$

The machine reading is 784N ( Newton ) .