A man of mass m is inside a box of same mass .The whole system is suspended with ideal strings and pulley as shown in above figure.The tension t1 in the string so as to keep the system in equilibrium is
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Answer:The tension t1 in the string so as to keep the system in equilibrium is mg
Explanation: As per the figure, the net force on the top most point is 2mg as the weight of both the man and box is same. So to keep entire system in balance the tension on T1 is half of the total force. That is mg.
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Given :
Mass of man :
= m
Mass of box :
=m
To Find :
Tension in the string so as to keep the system in equilibrium =?
Solution :
Magnitude of weight of man and box acting downward :
= mg
Here since the 2nd pulley is an ideal pulley so the force acting on it will be zero , so that :
Now for equilibrium upward force should balance the downward , so :
Therefore tension in the string is mg.
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