A man of mass m1 = 64.5 kg is skating at v1 = 7.60 m/s behind his wife of mass m2 = 53.0 kg, who is skating at v2 = 3.80 m/s. instead of passing her, he inadvertently collides with her. he grabs her around the waist, and they maintain their balance.
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This question test the concept of inelastic collision and the relationship between initial and final momentum.
Final momentum = initial momentum
Momentum = mass × Velocity
The initial total momentum before the collision is :
m₁v₁ + m₂v₂ = (64.5 × 7.60) + (53.0 × 3.80) = 691. 6
Final total momentum after collision :
Let total mass = m₃ and final velocity = v₃
Then final momentum = m₃v₃
m₃ = 64.5 + 53.0 = 117.5kg
From the concept :
Final momentum = initial momentum, we can get the final velocity.
691.6 = 117.5v₃
v₃ = 691.6 / 117.5
v₃ = 5.89m/ s
The two move at a velocity of 5.89 m / s after collision.
Final momentum = initial momentum
Momentum = mass × Velocity
The initial total momentum before the collision is :
m₁v₁ + m₂v₂ = (64.5 × 7.60) + (53.0 × 3.80) = 691. 6
Final total momentum after collision :
Let total mass = m₃ and final velocity = v₃
Then final momentum = m₃v₃
m₃ = 64.5 + 53.0 = 117.5kg
From the concept :
Final momentum = initial momentum, we can get the final velocity.
691.6 = 117.5v₃
v₃ = 691.6 / 117.5
v₃ = 5.89m/ s
The two move at a velocity of 5.89 m / s after collision.
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