A metal oxide has the formula z2o3 it can be reduced by hydrogen to give a free metal and water .0.15 96 of the metal oxide requires 6 mg of hydrogen for complete reduction.the atomic weight of the metal is
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The correct option is : (d) 55.8
Explanation:
Z2O3 + 3H2 → 2Z + 3H2O
Valency of metal in Z2O3 = 3
0.1596 g of Z2O3 react with 6 mg of H2 .
[1 mg = 0.001 g = 10-3 g]
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