Question

A man of mass m1 = 70 kg is skating at v1 = 8 m/s behind his wife of mass m2 = 5.0 kg, who is skating at v2 = 4.0 m/s. instead of passing her, he inadvertently collides with her. he grabs her around the waist, and they maintain their balance.

Answer 1

Simply use here law of conservation of momentum to find the final speed of collided body

total mass of collided body=50+70=120

let the final velocity of collided body be v

then ,intital momentum=final momentum

70×8+50×4=120×v

560+200=120v

v=760/120

v=63.3m/s

hope it helps you

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