Question

A man of weight 60kg in a small boat of mass 140kg that is at rest throws a 5kg stone in the horizontal direction with velocity of 14ms the velocity of the boat after immediate throw is

Answer 1

$\huge{\red{\mathfrak{Solution}}}$

➡️Take boat+men as system and their total mass be M

➡️mass of stone be m

$<b>$

By conservation of momentum–

Mu1+mu2=Mv1+mV2

0+5×14=200×v1+0

$v1 = \frac{14}{40} m {sec}^{ - }$

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