a man on ground throws a ball with speed u0 at angle theta with horizontal
a-find velocity at mid of max height
b- find time when v=u0cos theta
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Answer:
Answer
<V>=
T
R
=U
x
=v
1
For journey
<V>
1−n
=
T
1
+T
2
+....+T
n
R
1
+R
2
+...+R
n
=
g
2u
y
1
+
g
2u
y
2
+....
g
2u
yn
g
2u
x
1
u
y
1
+
g
2u
x
2
u
y
2
+....+
g
2u
x
n
u
y
n
U
x
⎣
⎢
⎢
⎡
1+
α
1
+
α
2
1
+....+
α
n
1
1+
α
2
1
+
α
4
1
+...
α
2n
1
⎦
⎥
⎥
⎤
=0.8v
1
⇒
⎣
⎢
⎢
⎢
⎢
⎢
⎡
1−
α
1
1
⎦
⎥
⎥
⎥
⎥
⎥
⎤
v
0
⎣
⎢
⎢
⎢
⎢
⎢
⎡
1−
α
2
1
1
⎦
⎥
⎥
⎥
⎥
⎥
⎤
=0.8v
1
⇒
1+α
α
=0.8⇒α=4
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