Question

A man pulls a roller by a force of 20 kg f applied a
60° with the ground. If he pulls it a distance of 10 m
in 1 minute, calculate the power dissipated.​

Answer 1

Explanation:

horizontal component of force =

20*10*cos 60 = 200*1/2 = 100 N

power = rate of work done

= 100*10/60 = 100/6 = 50/3 = 16.67 watt

Answer 2

The power dissipated by a man is 16.33 Watts.

Explanation:

It is given that,

Force acting on the roller, F = 20 kg

Angle with the ground, $\theta=60^{\circ}$

distance covered, d = 10 m

Time, t = 1 min = 60 s

The work done per unit time is called power dissipated.

$P=\dfrac{W}{t}$

$P=\dfrac{mgd\ cos\theta}{t}$

$P=\dfrac{20\times 9.8\times 10 \ cos(60)}{60}$

P = 16.33 Watts

So, the power dissipated by a man is 16.33 Watts. Hence, this is the required solution.

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