Physics, asked by rohank7531, 1 year ago

A man pulls a solid cylinder horizontally by a massless string as shown.The string is wrapped on the cylinder and the cylinder performs pure rolling (that is ,rolling without slipping).Mass of the cylinder is 100kg radius is pie metre and tension in string is 100n.Then the angular speed of the cylinder after one revolution will be

Answers

Answered by Vaswata11
5
Ok now look.
There's a force of 100 N pulling the solid cylinder. From here, we get
Tension × Lever Arm = Moment of Inertia of Solid cylinder × Angular Acceleration
=>100 kg × π m = ((100 kg × (π m)²)/2) × a
=>Angular Acceleration = (2/π) rad/s²
Now,
(Angular speed)² = 2 × Angular Acceleration × Angle Swept
=>v² = 2 × (2/π) × 2π
=>v = 2√2 rad/s
I hope you got your answer. Peace.
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