A man purchase 5horses and 10 cows for Rs 10,000. He sells the horses at 15% profit and the cows at 10%loss.Thus he gets Rs 375 as profit. Find the cost of 1horse and 1cow.
without allegation.
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Hi ,
Let us assume that ,
Cost price of each horse = Rs x
Cost price of each cow = Rs y
Gain of selling the horse ( g ) = 15%
Loss if selling the cow ( L ) = 10%
S.p of horse = x ( 100 + g )/100
= x ( 100 + 15 )/100
= 115x/ 100
S.p of 5 horses = 5 × 115x/100
= 23x/4 ---( 1 )
S.p of each cow = y ( 100 - L )/100
= y × ( 100 - 10 )/100
= 90y/100
S.p of 10 cows = 10 × 90y/100
= 9y ---( 2 )
Profit of selling horses = 23x/4 - 5x
= ( 23x - 20x )/4
= 3x/4 --- ( 3 )
Loss of selling cows = 10y - 9y
= y--( 5 )
According to the problem given ,
Man gets Rs 375 profit
( 4 ) - ( 5 ) = 375
3x/4 - y = 375
( 3x - 4y ) = 375 × 4
3x - 4y = 1500 ---( 6 )
Cost price of 5 horses and 10 cow's
is Rs 10000
5x + 10y = 10000
x + 2y = 2000
x = 2000 - 2y ----- ( 7 )
Substitute ( 7 ) in equation ( 6 ) ,we
get
3( 2000 - 2y ) - 4y = 1500
6000 - 6y - 4y = 1500
- 10y = 1500 - 6000
- 10y = - 4500
y = Rs 450
Now ,
Substitute y = 450 in equation ( 7 ) ,
we get
x = 2000 - 2 × 450
x = 2000 - 900
x = 1100
Therefore ,
Cost of each horse = x = Rs 1100
Cost of each cow = y = Rs450
I hope this helps you.
: )
Let us assume that ,
Cost price of each horse = Rs x
Cost price of each cow = Rs y
Gain of selling the horse ( g ) = 15%
Loss if selling the cow ( L ) = 10%
S.p of horse = x ( 100 + g )/100
= x ( 100 + 15 )/100
= 115x/ 100
S.p of 5 horses = 5 × 115x/100
= 23x/4 ---( 1 )
S.p of each cow = y ( 100 - L )/100
= y × ( 100 - 10 )/100
= 90y/100
S.p of 10 cows = 10 × 90y/100
= 9y ---( 2 )
Profit of selling horses = 23x/4 - 5x
= ( 23x - 20x )/4
= 3x/4 --- ( 3 )
Loss of selling cows = 10y - 9y
= y--( 5 )
According to the problem given ,
Man gets Rs 375 profit
( 4 ) - ( 5 ) = 375
3x/4 - y = 375
( 3x - 4y ) = 375 × 4
3x - 4y = 1500 ---( 6 )
Cost price of 5 horses and 10 cow's
is Rs 10000
5x + 10y = 10000
x + 2y = 2000
x = 2000 - 2y ----- ( 7 )
Substitute ( 7 ) in equation ( 6 ) ,we
get
3( 2000 - 2y ) - 4y = 1500
6000 - 6y - 4y = 1500
- 10y = 1500 - 6000
- 10y = - 4500
y = Rs 450
Now ,
Substitute y = 450 in equation ( 7 ) ,
we get
x = 2000 - 2 × 450
x = 2000 - 900
x = 1100
Therefore ,
Cost of each horse = x = Rs 1100
Cost of each cow = y = Rs450
I hope this helps you.
: )
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