Math, asked by tdougeastb8851, 1 year ago

A man purchase two machines at rs 1200 each.On one he gain 20%and on the other he loses 20%.How much he gain or lose in whole transaction.

Answers

Answered by debtwenty12pe7hvl
12

In the case where loss and gain percentage is common on same selling price, always a loss incurs in total deal. And this can be calculated by a short-cut:

Loss on total deal,

= (Common loss or gain % /10)2 = (20/10)2     [comman loss or gain is 20%]

= 4% ANS

                            OR by long method

Let the two items be X and Y respectively [X & Y are two machines ]

X be sold at 20% gain

Y be sold at 20 % loss

Cost price of x = 1200/120% =Rs 1000

Cost price of y = 1200/80% = Rs 1500

Gain on sale of x = Rs 1200-1000 =Rs 200

Loss on sale of y = Rs 1500 -1200=Rs 300

Net loss = Rs 300 - Rs 200 =Rs 100

Total Cost price =[Rs 1000 +Rs 1500] =Rs 2500

Net loss% =loss/ total CP*100

Net loss% =100/2500*100 =4% ANS



Answered by joytwenty12
4

100==20% gain ==>120

==20% loss==>96.

Loss = 4% (As 100 became 96)

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