Question

a man purchased 40 fruits; apples and oranges for rs 17. had he purchased as many as oranges as apples and as many apples as oranges he would have paid rs 15. find the cost of one pair of an apple and an orange

Answer 1

Let, no. of apples = m and no. of oranges = n

And let cost of an apple =Rs a and cost of an orange =Rs o

Now m+n= 40 ---- (I)

Also (a×m) + (o×n) = 17 ----- (ii)

And (a×n) + (o×m) = 15 ---. (iii)

Adding (ii) and (iii) we get,

a(m+n) + o (m+n)= 32
=>(a+o) × (m+n)= 32.....(IV)

now putting the value of (m+n) in equation (iv) from equation (I) we get,
a+o = (32/40)=Rs 0.8=80 paise

Answer 2

Refer to the above attachment