A man purchased 4mangoes at the rate of 5 rupees and sold 5mangoes at the rate of 4rs. .find loss percentage?
Answers
Answered by
2
cost price of 4 mangoes =5 rupees
selling price of 5 mangoes=4 rupees
loss= cost price - selling price
= 5 rupees - 4 rupees
= 1 rupees
loss percent = 1/5*100 =20%
selling price of 5 mangoes=4 rupees
loss= cost price - selling price
= 5 rupees - 4 rupees
= 1 rupees
loss percent = 1/5*100 =20%
Answered by
1
Always compare Selling price and Cost price for the same Quantity of the particular item ( here mangoes is the item ) .
Generally, in the answers to such questions people compare CP and SP for 1 item but you can compare for any fixed amount ( 100 , 200 , 541 , 98 , etc. ) let's say for x amount.
CP of 4 mangoes = rs. 5
CP of x mangoes = rs. (5/4)*x
SP of 5 mangoes = rs. 4
SP of x mangoes = rs. (4/5)*x
Now (5/4)*x>(4/5)*x
( x being a positive whole number )
Hence there occurs a loss as CP > SP ( for x mangoes ) .
Loss = [(5/4)-(4/5)]*x = (9/20)*x
So loss % = (loss/CP) * 100
= (9/20)*(4/5)*100 = 36
Similar questions