A 150 meter long train crosses a man walking at a speed of 6km/ h in the opposite direction in 6 seconds what is tge speed od train
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Let 'v' be the speed of the train with respect to the ground. The velocity of the man with respect to ground is -6 km/h (negative sign is included because the man and the train are moving in opposite directions). So, the velocity of the man with respect to the train is [v - (-6)] = (v + 6) km/h
Time taken by the man to cross the 0.15 Km train is = 6 s = (6/3600) h
Using, Distance = speed X time 0.15 = (v + 6) X (6/3600)
Implies, v = 84 Km/h
So, the speed of the train is 84 Km/h.
Let 'v' be the speed of the train with respect to the ground. The velocity of the man with respect to ground is -6 km/h (negative sign is included because the man and the train are moving in opposite directions). So, the velocity of the man with respect to the train is [v - (-6)] = (v + 6) km/h
Time taken by the man to cross the 0.15 Km train is = 6 s = (6/3600) h
Using, Distance = speed X time 0.15 = (v + 6) X (6/3600)
Implies, v = 84 Km/h
So, the speed of the train is 84 Km/h.
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