A man purchased a certain number of oranges at the rate of 2 for Rs.5 and sold them at the rate of 3 for Rs.8. In the process, he gained Rs.20. Find the number of oranges he bought.
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Answered by
61
Let the man purchase 6k oranges.
==> CP of 6k oranges = Cost of one orange x No. of oranges bought
= (5/2)x6k = Rs.15k
SP of 6k oranges = SP of one orange x no. of oranges sold
= (8/3) x 6k = 16k.
Therefore Profit = SP - CP = 16k -15k = 1k = Rs.20 (given)
==> k = 20.
Hence man purchased oranges = 6k = 6x20 = 120
==> CP of 6k oranges = Cost of one orange x No. of oranges bought
= (5/2)x6k = Rs.15k
SP of 6k oranges = SP of one orange x no. of oranges sold
= (8/3) x 6k = 16k.
Therefore Profit = SP - CP = 16k -15k = 1k = Rs.20 (given)
==> k = 20.
Hence man purchased oranges = 6k = 6x20 = 120
nandhinimouli:
tanq :)
1 doubt mam... hw did u take the value 6k ?
I shall explain. In fact, any letter can be assumed. But to facilitate in calculation, 6k has been taken. Why 6? This has been taken from the fact that cost price and selling price per orange are (5/2) and (8/3) which have factors 2 and 3 in the denominator. To cancel out 2 and 3 from calculation to avoid dealing with fractions, LCM of 2 and 3,i.e.,6 has been taken . You may take just k and proceed with calculation. You will get the same answer although with calculations involving fractions.
okay ma'am ... tanq and so kind of u ... :) :)
I like it very much that you had your doubts cleared
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