Question

a man purchased an article. he then sold article with rs 96 and made a profit. If the percentage of profit is as much as cost prize. Cost prize of the article is

Answer 1

let the cost price(CP ) of article be x.
as per ques.
selling price (SP) =96
profit %= {(SP-CP)*100}÷CP
$= > (x + 160)(x - 60) = 0$
$(96 - x )\div x \times 100= x$
$= > x ^{2} = 9600 - 100x$
$= >x ^{2} + 100x - 9600 = 0$
$= > (x + 160)(x - 60) = 0$
$= > x = - 160 \: or \: x = 60$
Since price cannot be negative
therefore X=60
CP =60

Answer 2

Answer:

here is your answer

Step-by-step explanation:

let the cost price(CP ) of article be x.

as per ques.

selling price (SP) =96

profit %= {(SP-CP)*100}÷CP

= > (x + 160)(x - 60) = 0=>(x+160)(x−60)=0

(96 - x )\div x \times 100= x(96−x)÷x×100=x

= > x ^{2} = 9600 - 100x=>x

2

=9600−100x

= > x ^{2} + 100x - 9600 = 0=>x

2

+100x−9600=0

= > (x + 160)(x - 60) = 0=>(x+160)(x−60)=0

= > x = - 160 \: or \: x = 60=>x=−160orx=60

Since price cannot be negative

therefore X=60

CP =60