A man reaches his destination which is 16 km away, 9 minutes late, if he travels at 8 kmph. What should his speed be if he wishes to reach 15 minutes ahead of the right time?
Answers
Step-by-step explanation:
d=16 km.
t=0.15h+x
s=8 km/h.
S=d/t
8=16/0.15+x
8(0.15+x)=16
0.15+x=2
x=1.85hs.
15m=0.25hs.
x-15m=1.85-0.25=1.60hs.
S=16/1.60=10km/h.
10 km/h should be his speed.
Concept:
Speed is determined by dividing the distance travelled by the time taken to travel it. It gives the amount of time it took to travel a certain distance divided by the distance travelled.
Speed is inversely correlated with time and directly correlated with distance. As a result, distance equals speed x time, and time equals distance divided by speed; as speed rises, distance travelled will shorten, and vice versa.
Speed α 1/time
Speed = distance/ time
Given:
A man reaches his destination which is 16 km away, 9 minutes late, if he travels at 8 kmph.
Find:
What should his speed be if he wishes to reach 15 minutes ahead of the right time?
Solution:
time taken in covering 16 km at speed of 8 kmph
= 16/8 hour
= 2 hours
= 2*60 minute
= 120 minute
this time is 9 minute late
means correct time is 120-9
= 111 minute
now he wants to be 15 minute ahead of right time
the required time = 111-15
= 96 minute
= 96/60 hours
= 16/10 hours
required speed = distance/time
= 16/(16/10)
= 10 kmph
Therefore , the required speed is 10kmph
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