Question

a man reads 3/8 of a book on a day and 4/5 of the remainder on the second day. If the numbers of pages still unread are 40,then how many pages did the book contain?​

Answer 1

Answer-320 pages

Step-by-step explanation:

Hunar,

If 3/8 of the book were read the first day, then 5/8 remained.

 

4/5 of 5/8 = 4/5 * 5/8 = 4/8

 

So now 3/8 + 4/8 = 7/8 have been read.

 

The 40 pages that remain must be 1/8 of the total.

 

So if p is the total number of pages:

 

p/8 = 40

 

p = 320 pages

 

hope that helps.

Answer 2

Answer:

The total number of pages in the book = 320.

Step-by-step explanation:

Given,

The number of pages read on the first day = $\frac{3}{8} of \ the \ book$

The number of pages read on the second day = $\frac{4}{5} \th \ of \ remaining$

The number of pages unread = 40

To find,

The total number of pages in the book

Solution:

The number of pages read on the first day = $\frac{3}{8}x$

The remaining unread pages after first day = x -    $\frac{3}{8}x$ = $\frac{8x - 3x}{8}$ = $\frac{5x}{8}$

The number of pages read on the second day = $\frac{4}{5} X \frac{5x}{8}$ = $\frac{x}{2}$

The number of pages unread = 40

Total number of pages =  No of pages read in the two days + The unread pages

Hence we have,

x =  $\frac{3}{8}x$ +  $\frac{x}{2}$ + 40

x - $\frac{3}{8}x$ -  $\frac{x}{2}$  =  40

$\frac{8x - 3x - 4x}{8}$ = 40

$\frac{x}{8} = 40$

x = 8 × 40 = 320

∴ The total number of pages in the book = 320

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