a man reared cow and Buffaloes. the number of Buffalo was 7 more than that one third of number of cows. what was the total number of animals if the number of buffoes was 21?
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Answered by
4
Let no of cows be = x;
So 1/3 of cows will be =x/3;
It says no of buffalo is 7 more than one third the no of cows;
So ;
21 = 7 + x/3;
21 = (21+x)/3;
21+x = 63;
X = 42;
Therefore the no of buffaloes = x = 42;
Hope this helps..
So 1/3 of cows will be =x/3;
It says no of buffalo is 7 more than one third the no of cows;
So ;
21 = 7 + x/3;
21 = (21+x)/3;
21+x = 63;
X = 42;
Therefore the no of buffaloes = x = 42;
Hope this helps..
Answered by
0
Answer:
buffaloes=21
cows=x/3+7
x/3+7=21
x=14×3
x=42
cows=42/3+7
cows=21
total=42
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