Show that 6no can't ending with the digit 0 and 5 for any natural number n.
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6^n =2^n * 3^n
any number must have 2 and 5 in its prime factorisation.
6 does not contain 5
therefore it cannot end with 0
any number must have 2 and 5 in its prime factorisation.
6 does not contain 5
therefore it cannot end with 0
Answered by
0
in peime.factorisation 6 factors.or multiples.end.with 6
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