a man riding a bike with a velocity 40 metre per second and moves with uniform acceleration of 4 metre per second square then the distance covered in 10th second is
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0
Answer:
since the body is moving with uniform velocity, ie. it covers equal distances in equal intervals of time. the distance covered in the 10th sec is
s=vt
s=40. 10
s=400m
Explanation:
Answered by
0
Answer:
42 metres
Explanation:
a = 4 m/s^2
v = 40 m/s
t = 10s
v = u + at
=> 40 = u + 4(10)
=> u = 0 m/s
distance = ut + 1/2at^2
=> distance = 1/2*4*100
=> distance = 200 m
this is the distance covered in 10s
distance covered in 11 seconds
= 1/2*4*121
= 242 m
distance covered in the 10 that second = distance covered in 11 seconds - distance covered in 10 seconds
= 242 - 200
= 42 metres.
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