Math, asked by jay9761, 11 months ago

a man runs round a cirvular field of radius 50 m at a speed of 12km/hour .what time is taken by the man to take 20 rounds of the field​

Answers

Answered by abhishek49930
0

Step-by-step explanation:

cicumfrence of the feild=22/7×50×2

22/7×100

2200/7=314.28

314.28×20=6285.6

6285.6÷12=523.8

maybe its correct then dont know

its wrong

i will send again aftrwards

Answered by Anonymous
2

Answer:

\large\boxed{\sf{31.4\;\;min}}

Step-by-step explanation:

Radius of Circular field, r = 50 m

.°. Circumference , c = 2πr = 100π m

Speed , v = 12 km/hr = 12×5/18 = 10/3 m/s

Distance covered in one round = c = 100π m

.°. Distance in 20 rounds =20×100π =2000π m

Time taken, t = Distance/Speed

 =  \dfrac{2000\pi}{ \frac{10}{3} } \\   \\  =  \frac{2000\pi \times 3}{10}  \\  \\  = 200\pi \times 3 \\  \\  = 600\pi \\  \\  = 600 \times  \frac{22}{7}  \\  \\  =  \sf{1885.71 \:  \:  \: sec.}

Time in minutes = t/60

 =  \frac{600 \times 22}{60 \times 7}  \\  \\  =  \frac{10 \times 22}{7}  \\  \\  =  \sf{31.4 \:  \: min}

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