Question

A man's age is 3 times his son's age .10 years ago his age was five times his son's age .find their current age

Answer 1

Here is your answer,


Let the present age of man be x yrs
And the present age of son be y yrs
ATQ
x = 3y -----------------------------i

10 years ago,
Man's age = (x-10) yrs
Son's age = (y-10) yrs

(x-10) = 5(y-10)
=> x-10 = 5y-50
=> x-5y+40 = 0 --------------------ii

Substituting the value of x in ii

3y-5y = -40
=> -2y = -40
=> -y = -40/2
=> -y = -20
=> y = 20

x=3y
= 3x20
= 60



Therefore, the present age of man is 60 years.
And the present age of son is 20 years.




HOPE IT HELPS YOU !!!

Answer 2

Here is your solutions

Let son’s age be x years.

Therefore, Aman’s age will be 3x years.

Ten years ago, their age was (x − 10) years and
(3x − 10) years respectively.

A/q

10 years ago, man age = 5 × son’s age 10 years ago

3x − 10 = 5(x − 10)

3x − 10 = 5x − 50

50 − 10 = 5x − 3x

40 = 2x

20 = x

Son’s age = x years = 20 years

Man age = 3x years = (3 × 20) years = 60 years

Hope it helps you