Question

A man's age is three times his son's age. ten years ago he was five times his son's age. find their present ages.

Answer 1

Let the son's age be x years.
⇒Man's age=3*x=3x years.
Son's age 10 years ago=x-10 years.
Man's age 10 years ago=3x-10 years.
Given,
$5(x-10)=3x-10$
⇒$5x-50=3x-10$
⇒$5x-3x=50-10$
⇒$2x=40$
⇒$x= \frac{40}{2}=20$
Son's present age:20 years and Man's present age:3*20=60 years.
Ans:Son's age is 20 years and Man's age is 60 years.
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