A man's age is three times his son's age .ten years ago his age was five times his son's age.find their current age
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let the man's age be x
son's age be y
x=3y....(1)
before 10 years
x-10=5(y-10)
x-10=5y-50
x-5y+40=0
by substitution method in (1)
3y-5y=-40
2y=40
y=20
x=60
son's age is 20 and father's age is 60
son's age be y
x=3y....(1)
before 10 years
x-10=5(y-10)
x-10=5y-50
x-5y+40=0
by substitution method in (1)
3y-5y=-40
2y=40
y=20
x=60
son's age is 20 and father's age is 60
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