Question

A man's age is three times older than his son's age . Ten years ago he was five times his son's age . Find their present age.

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• At present,

Let the son's age be 'x'.

Then, man's age = 3x


• 10 years ago,

Man's age = 3x - 10

Son's age = x - 10


• But, 10 years ago, man's age was 5 times his son's age.

=> 3x - 10 = 5 (x - 10)

=> 3x - 10 = 5x - 50

=> - 10 + 50 = 5x - 3x

=> 40 = 2x

=> x = 40/2

=> x = 20


• Hence, the present age of son = x = 20 years.

• And, present age of man = 3x = 3 × 20 = 60 years.

$<marquee>Hence, your answers are - 20 years and 60 years.</marquee>$
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Thank you.. ;-)