A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
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Answered by
72
Answer:
Step-by-step explanation:
Given :-
- A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be.
To Find :-
- Their Present age
Solution :-
Let present age of the son be x years
And present age of the man be 3x years
In 12 years
- Son’s age will be = (x + 12) years
- The man’s age will be = (3x + 12) years
According to the Question,
- ⇒ 3x + 12 = 2(x + 12)
- ⇒ 3x + 12 = 2x + 24
- ⇒ 3x – 2x = 24 – 12
- ⇒ x = 12
Hence, present age of the man = 36 years
Present age of the son = 12 years.
Answered by
21
Answer:
Man's age = 36
Son's age = 12
Step-by-step explanation:
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