Question

a man's age is three times that of his son and in twelve years he will be twice as old as his son would be.what are their present ages?

Answer 1

let his son 's age be x and his father 's will be 3x

after 12years

3x+12= 2 (x+12) 12+3x=2x+24

x=12 son 's present age= 12 and father 's present age = 36 years

hope this help you

Answer 2

Let the present age of son be x years ,

Then, the present age of father = 3 times his son's age = 3x years

After, 12 years the age of son = (x + 12)years

And,age of father = (3x + 12) years

According to question,

3x + 12 = 2(x + 12)
3x + 12 = 2x + 24
3x - 2x = 24-12
x = 12



Therefore, present age of son = x = 12 years

And, present age of father = 3x = 36years


Hope it helps.
:-)