A man's age is three times the sum of the age of s two son.After 5 years,s age will be twice the sum of the ages of s two sons.Find the age of father.
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let x and y be the age of two child than
according to first condition
man's age =3(x+y) .........1
after 5 years man's age =his initial age + 5 ....2
and the two child age would be x+5,y+5
than according to second condition
3(x+y)+5 = 2[(x+5) + ( y+5)]
3x + 3y +5 = 2x + 2y + 20
x + y = 15
man's age = 3× 15 = 45.
according to first condition
man's age =3(x+y) .........1
after 5 years man's age =his initial age + 5 ....2
and the two child age would be x+5,y+5
than according to second condition
3(x+y)+5 = 2[(x+5) + ( y+5)]
3x + 3y +5 = 2x + 2y + 20
x + y = 15
man's age = 3× 15 = 45.
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