A man's weight when taken at the pole is 600N . will his weight remain the same when measured at the equator ? will there be an increase or decrease in his weight ? Explain
Answers
Answered by
2
Step-by-step explanation:
Explanation:
At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.
Mathematically:
Force = mg = Gmm₁/r²
g = Gm₁/r²
At the equator, G = 6.67430 x 10⁻¹¹ & m(mass of earth) = 5.972 × 10^24 kg
r(radius of earth, from the view of eq.) = 6378 km. Based on these values(or their approximations:
g = 9.78 m/s²
But at the poles: radius = 6357 km, thus,
at poles, g' = 9.832 m/s (on calculations)
Similar questions