Question

A man saves 100rs on his son's first birthday, 300rs on second birthday, 600rs on third birthday, 1000 rs on fourth birthday and continued till his son's 15th birthday. what is the total amount he saved? please explain clearly.

Answer 1

money saved---- 1st bday = 100
2nd bday =300
4th=600
5th= 1000
6th= 1500
7th = 2100
8th= 2800
9th= 3600
10th= 4500
11th= 5500
12th= 6600
13th= 7800
14th= 9100
15th= 10500
because the gap of money is like this ------=== first rs 100 then 200 then 300 then 400 and like this till 1400

Answer 2

on first year he save = 100 Rs
2nd birthday= 100+200 Rs= 300rs
3rd birthday = 300+300 Rs = 600rs
4th birthday=600+400rs =1000rs
according to this pattern that on every coming birthday he increase money by Rs 200 ,300, 400 and so on...........
so5th birthday = 1000 +500 = 1500rs
6th = 1500+600 = 2100rs
7th= 2100+700= 2800rs
8th =2800+800=3600rs
9th = 3600+900= 4500rs
10th = 4500+1000= 5500rs
11th = 5500+1100= 6600rs
12th =6600+1200= 7800rs
13th = 7800 + 1300= 9100rs
14th = 9100+1400 = 10500rs
15th = 10500+1500 = 12000rs

so total money = 100+300+600+1000+1500+2100+2800+3600+4500+5500+6600+7800+9100+10500+ 12000
= 68000 Rs total money

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