Question

A man says,"I am thinking of a number . when I divide it by 3 and then add 5, my answer is twice the number i thought of". Find the Number

Answer 1

Answer:

Correct answer is. 3

Step-by-step explanation:

Let the number be x.

Then according to the problem,

3

x

+5=2x

or,

3

5x

=5

or, x=3.

So the number is 3.

Answer 2

Answer:

3

Step-by-step explanation:

As per the provided information in the given question we have :

• A number is when divided by 3 and then added 5, the result is twice the number.

We've been asked to calculate the number.

Basically, here we've to frame a linear equation to find the value of unknown number. In order to do that so, firstly let's suppose the number as x.

Here, we'll use transposition method to solve the linear equation. We just transpose the values from RHS to lHS and vice-versa by changing the arithmetic operator before it to solve the particular equation.

Now, according to the question,

― A number is when divided by 3 and then added 5, the result is twice the number.

$\longrightarrow \sf{\quad {\dfrac{x}{3} +5 = 2x }}$

Taking LCM in L.H.S and performing addition.

$\longrightarrow \sf{\quad {\dfrac{x + 15}{3} = 2x }}$

Now, transposing 3 from LHS to RHS.

$\longrightarrow \sf{\quad {x + 15= 2x \times 3 }}$

Performing multiplication in RHS.

$\longrightarrow \sf{\quad {x + 15= 6x }}$

Now, transposing x from LHS to RHS. Its sign will get changed.

$\longrightarrow \sf{\quad {15= 6x - x }}$

Performing subtraction in RHS.

$\longrightarrow \sf{\quad {15= 5x }}$

Transposing 5 from RHS to LHS. Its arithmetic operator will get changed.

$\longrightarrow \sf{\quad {\cancel{\dfrac{15}{5}}= x }}$

Dividing 15 by 5.

$\longrightarrow \quad\underline{\boxed { \textbf{\textsf{ 3 = x }}}}$

Therefore, the required number is 3.