Math, asked by ashokkumarsingh1635, 1 year ago

A man sells 5 articles for rs15 and makes a profit of 20%.find his gain or loss as percent,if he sells 8 such articles for rs18.40

Answers

Answered by satyabalaji999p3s6fx
60
Sp of one article is 15/5 = rs 3,
profit is 20% then Cp of one article is 3*100/120 = rs 2.5

now cp of 8 such articles = 2.5*8 = rs 20,
sp of 8 articles is given to be 18.40 so loss% =
(20-18.4)*100/20 =1.6*5= 8%.
Answered by Haezel
26

Answer:

The man sells the article for 8% loss.

Step-by-step explanation:

Let the Cost Price be represented by CP and The Selling Price be represented by SP  

SP of of 5 articles = Rs 15.

Thus, SP of 1 article =  R s \frac{15}{5}=\bold{R s 3}

Profit % = 20%

We know, SP = CP + Profit

SP =  \bold{C P+\frac{\text { Profit } \%}{100} \times C P}

\begin{array}{l}{3=\left(\frac{100+20}{100}\right) C P=\frac{120}{100} C P} \\ {3=\frac{12}{10} C P}\end{array}

CP of 1 article = R s \frac{3}{12} \times 10=\bold{R s 2.50}

Now, SP of 8 articles = Rs 18.40

Thus, SP of 1 article =  \frac{18,40}{8}=\text\bold{ { Rs } 2.30}

Since SP < CP, Thus, Loss = CP – SP = Rs 2.50 – Rs 2.30 = Rs 0.20

Loss % =  =\frac{R s 0.20}{R s 2.50} \times 100=\bold{8 \%}

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