A man sells two scooters at 36000 each one scooter made 15% profit and on the other he makes 15% loss find the profit or loss percentage in the whole transaction
Answers
Answer :
He suffered a loss of 7%
Step-by-step explanation:
Selling Price of 1 scooter = 3600rs.
Selling Price of both scooters = 3600 × 2
=7200rs.
NOW,
1st scooter,
SP =3600rs. ; Rate of loss = 15%
CP = 3600 - {15%of 3600}
=> 3600 - {15/100 ×3600}
=>3600 - 540
=>3060rs.
2nd scooter,
SP =3600 ; Rate of Profit = 15 %
CP = 3600 + {15 % of 3600}
=> 3600 +540
=>4140rs.
Total CP = (3060+ 4140)rs.
=7740rs.
SINCE, CP > SP
THEREFORE , LOSS
LOSS = CP-SP
= 7740 - 7200
=540 rs
LOSS% = loss / CP ×100
= 540/7740 ×100
=6.99%
or 7 %(estimated)
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Solution!!
In this question, selling price (SP) of two scooters is given and the percentage of profit and loss on both the scooters is given. We have to find the profit or loss percentage of the whole transaction. To find that, we need to find out the cost price (CP) of both the scooters.
First scooter:-
SP = Rs 36000
Profit% = 15%
So, Profit% =
15 =
0.15 =
0.15 CP = 36000 - CP
0.15 CP + CP = 36000
1.15 CP = 36000
CP = 36000 ÷ 1.15
CP = Rs 31304.35
Second scooter:-
SP = Rs 36000
Loss = 15%
So, Loss% =
15 =
0.15 =
0.15 CP = CP - 36000
36000 = CP - 0.15 CP
36000 = 0.85 CP
CP = 36000 ÷ 0.85
CP = Rs 42352.94
Now that we have the CP and SP of both the scooters, we can find out the profit or loss percentage of the whole transaction.
Total CP = CP of first scooter + CP of second scooter
Total CP = Rs 31304.35 + Rs 42352.94
Total CP = Rs 73657.29
Total SP = SP of first scooter + SP of second scooter
Total SP = Rs 36000 + Rs 36000
Total SP = Rs 72000
CP>SP
Loss = Total CP - Total SP
Loss = Rs 73657.29 - Rs 72000
Loss = Rs 1657.29
Loss% =
Loss% =
Loss% = 2.25%
Formulae to remember:-
→ Profit = SP - CP
→ Loss = CP - SP
→ Profit% =
→ Loss% =
FYI:-
SP is Selling Price
CP is Cost Price
If SP>CP, then it is profit.
If CP>SP, then it is loss.